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{"id":17327,"date":"2024-03-28T09:10:00","date_gmt":"2024-03-28T09:10:00","guid":{"rendered":"https:\/\/soicau1119.minhngocxoso.com\/cach-tinh-xac-suat-trung-so-lo-de-ai-cung-tinh-duoc\/"},"modified":"2024-03-28T09:10:00","modified_gmt":"2024-03-28T09:10:00","slug":"cach-tinh-xac-suat-trung-so-lo-de-ai-cung-tinh-duoc","status":"publish","type":"post","link":"https:\/\/dudoantrungthuong.top\/cach-tinh-xac-suat-trung-so-lo-de-ai-cung-tinh-duoc\/","title":{"rendered":"c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 l\u00f4 \u0111\u1ec1 \u2013 ai c\u0169ng t\u00ednh \u0111\u01b0\u1ee3c"},"content":{"rendered":"
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1<\/strong> nh\u01b0 th\u1ebf n\u00e0o? C\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 \u0111\u01a1n gi\u1ea3n ai c\u0169ng \u00e1p d\u1ee5ng \u0111\u01b0\u1ee3c? H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1, c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t x\u1ed5 s\u1ed1 chi ti\u1ebft cho anh em \u0111\u1ea7y \u0111\u1ee7.<\/p>\n \u0110\u1ec3 th\u1eafng l\u00f4 \u0111\u1ec1, b\u1ea1n c\u1ea7n ph\u1ea3i bi\u1ebft c\u00e1ch th\u1ed1ng k\u00ea x\u1ed5 s\u1ed1, soi c\u1ea7u ch\u1ed1t s\u1ed1. C\u1ed9ng v\u1edbi \u0111\u00f3 l\u00e0 t\u00edch l\u0169y kinh nghi\u1ec7m l\u00f4 \u0111\u1ec1 c\u00e1 nh\u00e2n \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n ch\u00ednh x\u00e1c. V\u00e0 \u0111\u1eb7c bi\u1ec7t l\u00e0 c\u1ea7n c\u00f3 s\u1ef1 may m\u1eafn. Vi\u1ec7c soi c\u1ea7u, d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 \u0111\u01a1n gi\u1ea3n l\u00e0 vi\u1ec7c b\u1ea1n t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 c\u00e1c con c\u00f3 t\u1ef7 l\u1ec7 xu\u1ea5t hi\u1ec7n cao nh\u1ea5t. Ph\u1ea3i t\u00ednh to\u00e1n ch\u00ednh x\u00e1c th\u00ec m\u1edbi mong tr\u00fang th\u01b0\u1edfng \u0111\u01b0\u1ee3c.<\/p>\n X\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 l\u00e0 t\u1ef7 l\u1ec7 ph\u1ea7n tr\u0103m (%) xu\u1ea5t hi\u1ec7n c\u1ee7a con s\u1ed1 trong m\u1ed7i k\u1ef3 quay s\u1ed1 m\u1edf th\u01b0\u1edfng. L\u00f4 \u0111\u1ec1 hay x\u1ed5 s\u1ed1 \u0111\u1ec1u d\u1ef1a tr\u00ean k\u1ebft qu\u1ea3 quay x\u1ed1 m\u1edf th\u01b0\u1edfng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. V\u00e0 c\u00e1c con s\u1ed1 n\u00e0y c\u00f3 quy lu\u1eadt xu\u1ea5t hi\u1ec7n c\u1ee7a n\u00f3. \u0110\u1ec3 ch\u1ecdn \u0111\u01b0\u1ee3c con s\u1ed1 s\u1ebd xu\u1ea5t hi\u1ec7n th\u00ec b\u1ea1n ph\u1ea3i t\u00ednh to\u00e1n \u0111\u01b0\u1ee3c x\u00e1c su\u1ea5t c\u1ee7a c\u00e1c con s\u1ed1.<\/p>\n \u2013 D\u1ef1 \u0111o\u00e1n 1 s\u1ed1 \u0111\u1ec1: x\u00e1c su\u1ea5t tr\u00fang l\u00e0 1%<\/p>\n \u2013 D\u1ef1 \u0111o\u00e1n 1 con l\u00f4: x\u00e1c su\u1ea5t tr\u00fang l\u00e0 27%. Trong \u0111\u00f3, ta x\u00e9t \u0111i\u1ec1u ki\u1ec7n ho\u00e0n h\u1ea3o l\u00e0 27 con s\u1ed1 xu\u1ea5t hi\u1ec7n kh\u00f4ng tr\u00f9ng nhau.<\/p>\n \u2013 N\u1ebfu ch\u01a1i l\u00f4 xi\u00ean 2, l\u00f4 xi\u00ean 3, l\u00f4 xi\u00ean 4 ho\u1eb7c \u0111\u1ec1 3 c\u00e0ng, \u0111\u1ec1 4 c\u00e0ng. Th\u00ec x\u00e1c su\u1ea5t tr\u00fang 1 con l\u00f4 s\u1ebd gi\u1ea3m xu\u1ed1ng.<\/p>\n \u2013 Trong tr\u01b0\u1eddng h\u1ee3p l\u00f4 2 nh\u00e1y, hay l\u00f4 3 nh\u00e1y. Th\u00ec x\u00e1c su\u1ea5t s\u1ebd gi\u1ea3m xu\u1ed1ng, v\u00ed d\u1ee5 v\u1edbi l\u00f4 2 nh\u00e1y l\u00e0 23, 76%. Vi\u1ec7c l\u00f4 nh\u00e1y xu\u1ea5t hi\u1ec7n (m\u1ed9t s\u1ed1 xu\u1ea5t hi\u1ec7n nhi\u1ec1u l\u1ea7n)<\/p>\n Nh\u01b0 k\u1ebft qu\u1ea3 tr\u00ean th\u00ec m\u1ecdi ng\u01b0\u1eddi c\u0169ng c\u00f3 th\u1ec3 th\u1ea5y. X\u00e1c s\u1ea5t tr\u00fang l\u00f4 \u0111\u1ec1 kh\u00f4ng cao nh\u01b0 ch\u00fang ta th\u01b0\u1eddng nghe t\u1eeb nh\u1eefng ng\u01b0\u1eddi b\u00e1n s\u1ed1 qu\u1ea3ng c\u00e1o. Nh\u01b0ng v\u1eabn c\u00f3 nhi\u1ec1u ng\u01b0\u1eddi th\u1eafng l\u00f4 \u0111\u1ec1. Th\u1eadm ch\u00ed l\u00e0 th\u1eafng li\u00ean t\u1ee5c nhi\u1ec1u l\u1ea7n.<\/p>\n \u0110\u01a1n gi\u1ea3n nh\u1eefng ng\u01b0\u1eddi thua nhi\u1ec1u th\u1eafng \u00edt h\u1ecd ch\u01b0a bi\u1ebft c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1<\/strong>. Hay c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t x\u1ed5 s\u1ed1 ch\u00ednh x\u00e1c m\u00e0 th\u00f4i. C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 n\u00f3i d\u1ec5 th\u00ec c\u0169ng d\u1ec5 m\u00e0 n\u00f3i kh\u00f3 th\u00ec c\u0169ng kh\u00f3. Nh\u01b0ng n\u1ebfu anh em bi\u1ebft c\u00e1ch \u00e1p d\u1ee5ng th\u00ec ch\u1eafc ch\u1eafn s\u1ebd t\u00ecm \u0111\u01b0\u1ee3c c\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c.<\/p>\n T\u1ef7 l\u1ec7 tr\u00fang s\u1ed1 t\u1ed1i \u0111a 100% (t\u00ednh l\u00e0 1) cho 27 l\u00f4 mi\u1ec1n B\u1eafc. Bao g\u1ed3m 100 s\u1ed1 t\u1eeb 00 \u2013 99.<\/p>\n T\u1ef7 l\u1ec7 thua (t\u1ea1ch l\u00f4) khi b\u1ea1n \u0111\u00e1nh 1 con l\u00f4 l\u00e0 99%<\/p>\n Tr\u01b0\u1edbc khi v\u00e0o c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 th\u00ec tr\u01b0\u1edbc h\u1ebft ph\u1ea3i t\u00ednh t\u1ef7 l\u1ec7 l\u00f4 tr\u01b0\u1ee3t. V\u00ec x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u01b0\u1ee3t th\u01b0\u1eddng cao h\u01a1n so v\u1edbi khi \u0111\u00e1nh th\u1eafng.<\/p>\n N\u1ebfu x\u00e9t trong \u0111i\u1ec1u ki\u1ec7n t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 \u0111\u01b0\u1ee3c xem l\u00e0 1. Th\u00ec n\u1ebfu c\u00e0ng t\u1ea1ch nhi\u1ec1u th\u00ec t\u1ef7 l\u1ec7 n\u00e0y s\u1ebd c\u00e0ng g\u1ea7n 1. \u0110i\u1ec1u n\u00e0y \u0111\u1ed3ng ngh\u0129a l\u00e0 n\u1ebfu t\u1ef7 l\u1ec7 th\u1eafng b\u1eb1ng 1 th\u00ec b\u1ea1n tr\u00fang s\u1ed1. T\u1eeb \u0111\u00f3 ta c\u00f3 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 ki\u1ebfn thi\u1ebft nh\u01b0 sau:<\/p>\n [1 \u2013 (99% ^ 27)] * 100 ~ 23,7%<\/p>\n Trong \u0111\u00f3:<\/p>\n T\u1eeb c\u00f4ng th\u1ee9c n\u00e0y ta c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng tr\u00fang 2, 3, 4 \u2026 con l\u00f4 l\u00e0<\/p>\n X\u00e1c su\u1ea5t tr\u00fang 2 con l\u00f4 = [1 \u2013 (98% ^ 27)] * 100 ~ 42%<\/p>\n X\u00e1c su\u1ea5t tr\u00fang 3 con l\u00f4 = [1 \u2013 (97% ^ 27)] * 100 ~ 56% \u2026<\/p>\n T\u1eeb c\u00e1c c\u00f4ng th\u1ee9c tr\u00ean, th\u00ec ch\u00fang t\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p c\u00f4ng th\u1ee9c chung. Trong c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 x\u1ed5 s\u1ed1 l\u00f4 \u0111\u1ec1 nh\u01b0 sau.<\/p>\n C\u00f4ng th\u1ee9c t\u1ed5ng: [1 \u2013 [{100-n} % ^ 27)] * 100<\/strong><\/p>\n Trong \u0111\u00f3:<\/p>\n N\u1ebfu b\u1ea1n ch\u01a1i c\u00e1c lo\u1ea1i l\u00f4 xi\u00ean th\u00ec c\u00f3 th\u1ec3 tham kh\u1ea3o c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 sau. \u0110\u1ea7u ti\u00ean, x\u00e9t x\u00e1c su\u1ea5t l\u00f4 tr\u01b0\u01a1t.<\/p>\n => X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2 = 57,9% + 36,1% ~ 94%<\/p>\n T\u1eeb 3 c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 tr\u00ean, ta suy ra:<\/p>\n => T\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean 2 = 100% \u2013 94% = 6%<\/strong> (ch\u00ednh x\u00e1c h\u01a1n l\u00e0 x\u1ea5p x\u1ec9 6%)<\/p>\n Do t\u1ef7 l\u1ec7 tr\u00fang th\u1ea5p n\u00ean l\u00f4 xi\u00ean 2 th\u01b0\u1eddng c\u00f3 gi\u00e1 tr\u1ecb tr\u00fang s\u1ed1 cao. V\u00e0 \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi tham gia ch\u01a1i th\u1eed v\u1eadn may.<\/p>\n X\u00e1c su\u1ea5t l\u00f4 tr\u01b0\u1ee3t c\u1ee7a l\u00f4 xi\u00ean 3. Bao g\u1ed3m t\u1ed5ng x\u00e1c su\u1ea5t c\u00e1c tr\u01b0\u1eddng h\u1ee3p l\u00f4 tr\u01b0\u1ee3t.<\/p>\n X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 3 = (0,97^27) + (3 * 0,2376 * 0,98^27) + (3 * 0,058 * 0,99^27) = 0,9851 ~ 98,51% (x\u1ea5p x\u1ec9 98, 51%)<\/p>\n => X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3 = 100% \u2013 98,51% = 1,49%<\/strong> (ch\u00ednh x\u00e1c l\u00e0 x\u1ea5p x\u1ec9 1,49%)<\/p>\n X\u00e1c su\u1ea5t tr\u00fang c\u1ee7a l\u00f4 xi\u00ean 3 ch\u1ec9 1,49%. Tuy nhi\u00ean kh\u00f3 tr\u00fang l\u1ea1i th\u01b0\u1eddng \u0111i \u0111\u00f4i v\u1edbi gi\u1ea3i th\u01b0\u1edfng l\u1edbn. N\u00ean kh\u00f4ng \u00edt \u00f4ng v\u1eabn th\u00edch ch\u01a1i xi\u00ean 3, \u0111\u1eb7c bi\u1ec7t l\u00e0 nh\u1eefng ng\u01b0\u1eddi c\u00f3 nhi\u1ec1u kinh nghi\u1ec7m soi c\u1ea7u v\u00e0 m\u00e1t tay trong vi\u1ec7c ch\u1ed1t s\u1ed1.<\/p>\n V\u1edbi l\u00f4 xi\u00ean 3 \u0111\u01a1n gi\u1ea3n anh em c\u00f3 th\u1ec3 hi\u1ec3u l\u00e0 \u0111\u00e1nh 100 l\u1ea7n th\u00ec \u0103n 1 l\u1ea7n. th\u00ec v\u1edbi l\u00f4 xi\u00ean 4 th\u00ec x\u00e1c su\u1ea5t tr\u00fang l\u00e0 c\u1ef1c k\u00ec kh\u00f3. N\u00ean t\u00f4i c\u0169ng kh\u00f4ng \u0111\u01b0a ra c\u00f4ng th\u1ee9c to\u00e1n h\u1ecdc \u1edf \u0111\u00e2y.<\/p>\n Th\u00e0nh th\u1eadt m\u00e0 n\u00f3i kh\u00f4ng nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i l\u00f4 xi\u00ean 4. M\u1eb7c d\u00f9 gi\u1ea3i th\u01b0\u1edfng tr\u00fang th\u01b0\u1edfng l\u1edbn, nh\u01b0ng t\u1ef7 l\u1ec7 tr\u00fang r\u1ea5t th\u1ea5p. N\u00ean cho d\u00f9 l\u00e0 nh\u1eefng ng\u01b0\u1eddi chuy\u00ean gia l\u00f4 \u0111\u1ec1 c\u0169ng \u00edt khi ch\u01a1i. Vi\u1ec7c ch\u01a1i l\u00f4 xi\u00ean 4 th\u01b0\u1eddng mang t\u00ednh \u0111\u1ed5i gi\u00f3, l\u00e2u l\u00e2u n\u1ed5i h\u1ee9ng n\u00ean ch\u01a1i. Ch\u1ee9 \u00edt ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng xuy\u00ean.<\/p>\n Nhi\u1ec1u ng\u01b0\u1eddi c\u00f3 s\u1edf th\u00edch nu\u00f4i 1 con l\u00f4 k\u1ebft nhi\u1ec1u ng\u00e0y li\u00ean ti\u1ebfp, g\u1ecdi chung l\u00e0 N ng\u00e0y. N\u1ebfu nh\u01b0 ta t\u01b0\u1edbng l\u01b0\u1ee3ng N ng\u00e0y \u0111\u1ec3 c\u00f3 th\u1ec3 t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 1 l\u1ea7n. Th\u00ec x\u00e1c su\u1ea5t \u0111\u1ea1t g\u1ea7n 100%.<\/p>\n C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1<\/strong> hay c\u00e1c c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 kh\u00e1c \u0111\u1ec1u \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c to\u00e1n h\u1ecdc. \u0110\u1eb7c bi\u1ec7t l\u00e0 c\u00e1c h\u00e0m Logarit (c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 t\u00ecm hi\u1ec3u th\u00eam). C\u00f9ng th\u1eed x\u00e9t v\u1ec1 b\u00e0i to\u00e1n l\u00f4 \u0111\u1ec1 sau.<\/p>\n G\u1ecdi : A<\/strong> l\u00e0 bi\u1ebfn c\u1ed1 trong n ng\u00e0y m\u00e0 ng\u01b0\u1eddi ch\u01a1i kh\u00f4ng tr\u00fang l\u1ea7n n\u00e0o.<\/p>\n B<\/strong> l\u00e0 bi\u1ebfn c\u1ed1 ng\u01b0\u1eddi ch\u01a1i tr\u00fang s\u1ed1 \u00edt nh\u1ea5t 1 l\u1ea7n.<\/p>\n Ta c\u00f3 x\u00e1c su\u1ea5t \u0111\u1ec3 tr\u01b0\u1ee3t t\u1ea5t c\u1ea3 27 con l\u00f4 trong ng\u00e0y l\u00e0: 0,99 ^ 27 (0,99 m\u0169 27).<\/p>\n T\u1eeb \u0111\u00f3 suy ra:<\/p>\n P(B) > m \u21d4 0,99^27n < 1\u2212m \u21d4 n > log 0,99(1\u2212m)\/27<\/p>\n (P l\u00e0 k\u00fd hi\u1ec7u x\u00e1c su\u1ea5t trong to\u00e1n h\u1ecdc, P(A) l\u00e0 x\u00e1c su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 A)<\/em><\/p>\n V\u1edbi m = 0,9999 = 99,99% => n > 33, 9<\/p>\n Suy ra:<\/strong> trong kho\u1ea3ng 34 ng\u00e0y th\u00ec x\u00e1c su\u1ea5t ng\u01b0\u1eddi ch\u01a1i tr\u00fang s\u1ed1 \u00edt nh\u1ea5t 1 l\u1ea7n l\u00e0 kho\u1ea3ng 99,99%. Hay d\u1ec5 hi\u1ec3u h\u01a1n l\u00e0 n\u1ebfu b\u1ea1n li\u00ean t\u1ee5c nu\u00f4i 1 con s\u1ed1 th\u00ec sau 34 ng\u00e0y t\u1ef7 l\u1ec7 th\u1eafng l\u00e0 c\u1ef1c \u0111\u1ea1i.<\/p>\n Nh\u01b0 \u0111\u00e3 n\u00f3i vi\u1ec7c tr\u00fang s\u1ed1 c\u0169ng mang t\u00ednh ch\u1ea5t may m\u1eafn. V\u00e0 nhi\u1ec1u ng\u01b0\u1eddi c\u00f3 c\u00e1ch soi c\u1ea7u ch\u00ednh x\u00e1c v\u1eabn c\u00f3 th\u1ec3 th\u1eafng ti\u00ean ti\u1ebfp nhi\u1ec1u ng\u00e0y.<\/p>\n \u0110\u1ec3 tr\u00fang s\u1ed1 b\u1ea1n c\u00f3 nhi\u1ec1u c\u00e1ch \u0111\u00e1nh. \u0110\u1eb7c bi\u1ec7t l\u00e0 nh\u1eefng ng\u00e0y b\u1ea1n thi\u1ebfu may m\u1eafn, mu\u1ed1n gi\u1ea3i \u0111en l\u00f4 \u0111\u1ec1. Th\u00ec c\u0169ng c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng c\u00e1c c\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1.<\/p>\n \u0110\u1ec3 d\u1ec5 d\u00e0ng h\u01a1n trong vi\u1ec7c t\u00ecm c\u00e1c con s\u1ed1 may m\u1eafn. B\u1ea1n n\u00ean s\u1eed d\u1ee5ng c\u00e1c ph\u1ea7n m\u1ec1m m\u00e1y t\u00ednh l\u00f4 \u0111\u1ec1 s\u1eed d\u1ee5ng ph\u1ea7n m\u1ec1m, c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 l\u00f4 \u0111\u1ec1 hi\u1ec7n \u0111\u1ea1i nh\u1ea5t. Ch\u1ec9 v\u1edbi v\u00e0i thao t\u00e1c l\u00e0 b\u1ea1n \u0111\u00e3 c\u00f3 th\u1ec3 ti\u1ebft ki\u1ec7m \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u th\u1eddi gian t\u00ednh to\u00e1n.<\/p>\n Tr\u00ean \u0111\u00e2y l\u00e0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1 theo ph\u01b0\u01a1ng ph\u00e1p t\u00ednh x\u00e1c su\u1ea5t to\u00e1n h\u1ecdc. \u0110\u1ec3 m\u1ecdi ng\u01b0\u1eddi c\u00f3 th\u1ec3 tham kh\u1ea3o v\u00e0 \u00e1p d\u1ee5ng n\u1ebfu mu\u1ed1n. \u0110\u1ec3 anh em d\u1ec5 d\u00e0ng t\u00ecm \u0111\u01b0\u1ee3c nh\u1eefng con l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng v\u1ec1 nh\u1ea5t \u0111\u1ec3 \u0111\u00e1nh h\u00e0ng ng\u00e0y.<\/p>\n<\/p>\n
X\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec?<\/span><\/h2>\n
C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang s\u1ed1<\/span><\/h2>\n
C\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t ch\u01a1i \u0111\u1ec1<\/span><\/h3>\n
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C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 xi\u00ean 2<\/span><\/h3>\n
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C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/span><\/h3>\n
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C\u00e1ch t\u00ednh l\u00f4 xi\u00ean 4<\/span><\/h3>\n
B\u00e0i to\u00e1n t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1<\/span><\/h2>\n
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L\u01b0u \u00fd<\/span><\/h2>\n
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ch\u1ed1t s\u1ed1 mi\u1ec1n b\u1eafc\u00a0t\u1ef1 tin tr\u00fang h\u00f4m nay<\/span><\/strong><\/h4>\n